Question

A ray of light enters into benzene from air if the refractive index of benzene is 1.50

Answer 1

Absolute Refractive Index

n = $\dfrac {c} {v}$

Where
n = Refractive Index
c = the speed of light in Vacuum
v = the speed of light in Medium

1.50 = $\dfrac{3×10^8}{v}$

V = $\dfrac{3×10^8} {1.5}$

V = 2×$10^8$

Therefore speed of Light in Benzene is 2×$10^8$

Hope it helps you!!!

Answer 2

Answer:

33.3 % .

Explanation:

Given :

Refractive index of benzene = 1.50

We know :

Speed of light = 3 × 10⁸ m / sec

We know formula for n :

n = speed of light in vacuum / speed of light in benzene

n = c / v

1.5 = 3 × 10⁸ / v

v = 2 × 10⁸ m / sec

Now ,

Percentage ( % ) decrease = 1  × 10⁸ / 3  × 10⁸  × 100 %

% decrease = 33.3 % .