A ray of light enters into benzene from air.If the refractive index of benzene is 1.50,by what percentage does the speed of light reduce on entering the benzrne
Answers
Answered by
1
Refractive index, n =
Now,
Refractive index of benzene = 1.50
and,
Speed of light in air / vacuum = 3 × m/s
So,
=
= 2 * m/s
Now,
The percentage decrease in the speed of light =
= %
= 33.3 %
Hence,
The percentage decrease when light enters benzene from air is 33.3 %
Answered by
0
Answer:
33.3 % .
Explanation:
Given :
Refractive index of benzene = 1.50
We know :
Speed of light = 3 × 10⁸ m / sec
We know formula for n :
n = speed of light in vacuum / speed of light in benzene
n = c / v
1.5 = 3 × 10⁸ / v
v = 2 × 10⁸ m / sec
Now ,
Percentage ( % ) decrease = 1 × 10⁸ / 3 × 10⁸ × 100 %
% decrease = 33.3 % .
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