Physics, asked by usha2003kvs, 1 year ago

A ray of light falls normally on the surface of a transparent glass slab. Draw a ray diagram to show its path and also mark angle of incidence and angle of emergence.

Answers

Answered by sujankrishna79
15

Explanation:

this is your answer dude

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Answered by sourasghotekar123
0

Answer:

A ray of light falls normally on the surface of a transparent glass slab. Draw a ray diagram to show its path and also mark angle of incidence and angle of emergence.

Explanation:

  • When a ray of light normally on the surface of a transparent glass slab then the angle of incidence and angle of reflection-
  • If the ray of light falls normally on the surface of transparent glass slab, I that is angle of incidence is equal to zero that is I=0
  • Then r that is angle of reflection is also equal to zero that is r=0
  • Therefore u is equal to the ratio of Sin of angle of incidence and sin of angle of reflection. That is-
  • u= \frac{sin i}{sin r}
  • Therefore angle of emergence is also equal to zero.
  • That is angle of emergence =0

Hence, When a ray of light normally on the surface of a transparent glass slab then the angle of incidence and angle of reflection is zero.

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