A ray of light falls obliquely on the glass slab.the perpendicular distance between the emergent ray of light and the original path of incodent ray is 2mm. What is the lateral displacement of the ray of light
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Explanation:
It gives the deviation between the incident and emergent ray of light when it gets refracted through a glass slab.
Observe the given figure:
In the figure, the distance BC is called the lateral displacement.
The value of BC can be proved to be
BC=tcos(r)sin(i−r)
From the above expression, one can conclude that the lateral displacement is dependent on
(1) Thickness of the glass slab
(2) Angle of incidence
(3) Refractive index of the glass slab.
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I was about to give the same answer man. Thank You Genius lady
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