Question

A ray of light falls on a medium of refractive index 4/3 at an agnle of 30°. Find the angle of refraction. ​

Answer 1

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Given ,

Refractive index = 4/3

Angle of incidence = 30°

We know that ,

The ratio of sin of angle of incidence to the sin of angle of refraction is termed as refractive index

$\large \mathtt{\fbox{Refractive \: index = \frac{Sin \: of \: angle \: of \: incidence}{Sin \: of \: angle \: of \: refraction} }}$

Thus ,

$\sf \hookrightarrow \frac{4}{3} = \frac{ \sin(30) }{Sin \: of \: angle \: of \: refraction } \\ \\ \sf \hookrightarrow Sin \: of \: angle \: of \: refraction = \frac{3}{8} \\ \\ \sf \hookrightarrow angle \: of \: refraction = { \sin}^{ - 1} \frac{3}{8}$

Hence , the angle of refraction is sin inverse 3/8

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Answer 2

Answer:

Explanation:

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