Question

A ray of light falls on a transparent sphere with centre at C as shown in figure. The ray emerges from the sphere parallel to line AB. The refractive index of sphere is

Answer 1

Answer:

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Explanation:

Using Snell's Law,

sini=μsinr.......... Equation 1

Since perpendicular at any point on a circle passes through the center, CN is normal at E.

This makes ∠EDC=∠CED.

From exterior angle theorem, ∠BCE=2r

Again from Snell's law applied at point E,

μsinr=sin2r

Using Equation 1 gives sin2r=sini

Therefore r=30∘

Therefore μ=sin30∘sin60∘=3