A ray of light falls on the surface of a spherical glass paper weight making an angle (alpha) with the normal and is refracted in the medium at an angle beta.
Find the angle of deviation of the emergent ray from the direction of the incident ray ?
Answers
Answer:
You need to look into the laws of refraction of light to answer this particular question…which states that when a ray of light enters from rarer medium to a denser medium, it bends towards the normal.
Step-by-step explanation:
So when we look at this case, paper is air medium and is rarer, while the paper weight is much denser medium as compared to air.
So the moment light ray is incident from air to paper weight, then it tends to enter from rarer medium to denser medium. This will make the ray of light to bend towards the normal. This will make an angle alpha towards the normal. Now on the other side the ray of light gets deviated and bends towards the normal (perpendicular) such that it forms an angle Beta.
Once the light has reached on the other side of the paper weight it again tends to enter from the denser medium that is paper weight to the rarer medium that is the air. So the ray of light will bend away from the normal.
The deviated ray will in fact create an angle Beta 2 which is away from the normal.
Looking at the maths here, angle Beta is equal to Angle Alpha 1 and so angle Beta 1 will be equal to angle Alpha. That means that deviated angle has to be equal to the angle incident ray forms with the normal.
... figure attached..
Answer:
Step-by-step explanation:
i=e=alpha
r1=r2=beta
Delta=(alpha-beta)+(alpha-beta)
Delta=2(alpha-beta)
Bcoz the sum of two interior angles is equal to exterior angle.