Question

A ray of light incident at a certain angle on a prism having a refracting angle 53° suffers minimum deviation. If the angle of minimum deviation is 41°, what is the angle of incidence?

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Answer 1

Conditions for minimum deviation:

• angle of incidence(i) = angle of emergence(e)
• r1 = r2 = A/2
• A = refracting angle.
• $\rm \delta_{min} = minimum \: deviation$

$\boxed{\bf \delta_{min} = 2i-A}$

Solution:

$\implies\sf \delta_{min} = 2i-A$

$\implies\sf 41\degree = 2i-53\degree$

$\implies\sf 2i = 41\degree + 53\degree$

$\implies\sf i = \dfrac{94\degree}{2} = 47\degree$

★ Angle of incidence is 47°

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Answer 2

Explanation:

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Conditions for minimum deviation:

angle of incidence(i) = angle of emergence(e)

r1 = r2 = A/2

A = refracting angle.

$\rm \delta_{min} = minimum \: deviation$

$\boxed{\bf \delta_{min} = 2i-A}$

Solution:

$\implies\sf \delta_{min} = 2i-A$

$\implies\sf 41\degree = 2i-53\degree$

$\implies\sf 2i = 41\degree + 53\degree$

$\implies\sf i = \dfrac{94\degree}{2} = 47\degree$

★ Angle of incidence is 47°

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