A ray of light incident at an angle θ on a refracting face of a prism emerges from the other face normally. If the angle of the prism is 5° and the prism is made of a material of refractive index 1.5, the angle of incidence is
Answers
The angle of incidence is 7.5°
Explanation:
=> It is given that,
the angle of the prism, A = 5°
refractive index of material of prism, μ = 1.5
i₂ = 0°
r₂ = 0°
r₁ + r₂ = A
r₁ = A - r₂
= 5 - 0 = 5°
=> Now, μ = sin i₁/sin r₁
sin i₁ = μ sinr₁
sin i₁ = 1.5 * sin 5°
sin i₁ = 1.5 * 0.087
sin i₁ = 0.1305
i₁ = sin⁻¹ (0.1305)
i₁ = 7.5°
Thus, the angle of incidence is 7.5°
Learn more:
Q:1 A ray of monochromatic light is incident on one refracting face of a prism of angle 75 degree.it passes through the prism and is incident on the other face at the critical angle .if the refractive index of the material of the prism is root 2 the angle of incidence on the first face of the prism is
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Q:2 A ray of light is incident normally on one face of an equilateral prism of refractive index 1.5. What is the angle of deviation of the ray?
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The angle of incidence is 7.5°
Explanation:
=> It is given that,
the angle of the prism, A = 5°
refractive index of material of prism, μ = 1.5
i₂ = 0°
r₂ = 0°
r₁ + r₂ = A
r₁ = A - r₂
= 5 - 0 = 5°
=> Now, μ = sin i₁/sin r₁
sin i₁ = μ sinr₁
sin i₁ = 1.5 * sin 5°
sin i₁ = 1.5 * 0.087
sin i₁ = 0.1305
i₁ = sin⁻¹ (0.1305)
i₁ = 7.5°
Thus, the angle of incidence is 7.5°