A ray of light incident at an angle θ on a refracting face of prism emerges from the other face normally. If the angle of the prism is 5 and the prism is made of material of refractive index 1.5, the angle of incidence is
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Answer:
We have deviation, δ=(M−1)A
δ=(1.5−1)5
∘
=2.5
∘
The angle of the prism is 50°.The ray emerges from refracting face of a prism normally.
Then, i
2
=r
2
=0
As, A=r
1
+r
2
=0
r
1
=A
r
1
=50°
But i
1
=μr
1
=
2
3
×5=7.5°
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