Question

A ray of light incident on a transparent block at an angle of incidence . If  of block is  then angle of deviation of the refracted ray is​

Answer 1

Using Snell's Law :

sin r

sin i

=

v

2

v

1

=

μ

1

μ

2

μ

2

sin r=μ

1

sin i

1.732×sinr=1×sin60

′

sin r=

2

1

r=30

∘

so angle of deviation=60

∘

−30

∘

= 30

∘