Question

A ray of light incident on the first mirror and parallel to the second of reflected from the second mirror parallel to first mirror. The angle between the mirror is

Answer 1

Here the mirrors are inclined at an angle (C) θ so,

as OB || CZ (and AB is the transversal), angle ABO = θ as well

and by first law of reflection, angle ABO = angle DBC = θ



so, in triangle BCD,

angle B = angle C = θ



now,

angle FEO = angle EDZ = θ (as OB || CZ and FD is the transversal )

this would mean that

as EDZ = BDC

so BDC = θ



thus, in traingle BCD

B= C = D = θ

so, B + C + D = 3θ = 180

or

θ = 60 deg.