A ray of light is incident at 35o on a glass slab. Calculate the angle of refraction and deviation. Given refractive index of glass = 1.52.
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Answer:
Given,
refractiveindexn=
sin(r
2
)
sin(i)
=1.52;.....(1)
i=r
1
;
now, reflected & refracted ray are mutually perpendicular
⇒(90−r
1
)+(90−r
2
)=90⇒r
1
+r
2
=90⇒i+r
2
=90
⇒r
2
=90−i;
substitutinginequation(1);
⇒
sin(90−i)
sin(i)
=
cos(i)
sin(i)
=tan(i)=1.52;
⇒i=tan
−1
(1.52)=56
o
40
′
Explanation:
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