Physics, asked by sathvi96, 9 months ago

A ray of light is incident at 50on the middle of
one of the two mirrors arranged at an angle of 60
between them. The ray then touches the second
mirror. get reflected back to the first mirror, making
an angle of incidence of​

Answers

Answered by pp6609034
1

Answer:

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JEE Main & Advanced Physics Ray Optics Question Bank Plane Mirror

question_answer A ray of light is incident at 50° on the middle of one of the two mirrors arranged at an angle of 60° between them. The ray then touches the second mirror, get reflected back to the first mirror, making an angle of incidence of [MP PET 2005]

A) 50∘

B) 60∘

C) 70∘

D) 80∘Let required angle be q

From geometry of figure InΔABC;a=180∘(60∘+40∘)=80∘ ⇒β =90∘80∘=10∘ InΔABD;∠A=60∘,∠B=(a+2β) =(80+2×10)=100∘and∠D=(90∘θ) ∵∠A+∠B+∠D=180∘ ⇒60∘+100∘+(90∘θ)=180∘⇒θ=70

Answered by ashutoshmishra24
2

Answer:

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Explanation:

All angles in degrees as placed in the above figure

From the question where C=60 and a=50.

Then b=90-a=40

b'=40

C+b'+d=180

d=180-C-b'=180-60-40=80

Then e=90-d=90-80=10

e'=10

where as C'=180-d-e-e'= 180-80-10-10=80

So the ray get touches then the second mirror gets reflected is

Therefore in a triangle XYZ we have C+d+e+e'+f=180

f=180-C-d-e-e'

=180-60-80-10-10

=20

So the making angle of incidence F is 70°

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