Question

A ray of light is incident at an angle 30degree on a prism with angle 50degree. If it gets deviated by an angle of 15 degree,calculate the angle at which the ray will emerge​

Answer 1

Answer:

angle of prism A is 30

angle of incidence is 60 degree

angle of deviation is 30 degree

i

1

+i

2

=A+δ

the angle of emegrance

i

2

=A+δ−i

1

=30+30−60=0

'the emergent ray

r

1

+r

2

=A

i

2

=0,r

2

=0

r

1

=A=30

0

using snells law

n=

sinr

1

sini

1

=

sin30

sin60

=1.732

since emergent ray is normal

δ=δ

m

=30

0

sin30/2

sin(30+30/2)

=1.732

=√3