Question

A ray of light is incident at an angle of 30 degrees at an air-glass interface. Determine the:
a. angle of refraction
b. Angle of deviation
(n =1.5)

Answer 1

Answer:

The angle of refraction is 19.27°.

This can be determined using Snell's law which states:

Refractive index = sin i/sin r ( where i is the angle of incidence and r is the angle of refraction).

[ Since the medium has not been mentioned here, we consider it to be glass( default medium)]

Refractive index of glass= 1.5

So, 1.5 = sin 30/sin r

So, sin r = 0.33

So r = sin-1( 0.33) = 19.27°.

angle of deviation is:

refractive index is Sin(i)/Sin(r)

so, 1.5=Sin(30)/Sin(r)

this implies sin(r)=0.5/1.5

r=sin^-1(1/3)

r=19.47