Question

A ray of light is incident normally on one of the equal faces of a right isosceles prism of refractive index 1.5. The angle between incident and emergent rays is:-
(a) 45
(b) 90
(c) 180
(d) 0

Answer 1

Answer:

(b) 90°

Explanation:

SinC = n₂/n₁

C = sin⁻¹ (1/1.5)

C = 41.8°

45° > C

Hence rays will be reflected by AC from the figure angle between the incident and emergent rays = 90°