a ray of light is incident on a plane mirror at 45 another mirror is kept at a angel of 90 to the first mirror draw the path of the ray as it's reflects from the two mirror.show the position of the 3 image formed
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Answer:
From parallel line theory we can say that
∠CBP=∠BCD
As CD is parallel to PQ.
SO,
3×45
∘
=2α
α=
2
3
(45)=67.5
∘
Now the inclination of mirror with horizontal so that the ray is reflected horizontally is.
90
∘
−67.5
∘
=22.5
∘
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