a ray of light is incident on a plane mirror at 45 degrees.another mirror is kept at an angle of 90 degrees to the first mirror.draw the path of ray as it reflects from the two mirrors.show the position of the 3 images formed class 8
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Answer:
From parallel line theory we can say that
∠CBP=∠BCD
As CD is parallel to PQ.
SO,
3×45
∘
=2α
α=
2
3
(45)=67.5
∘
Now the inclination of mirror with horizontal so that the ray is reflected horizontally is.
90
∘
−67.5
∘
=22.5
∘
solution
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