Question

A ray of light is incident on a prism of refractive index μ=√2 It is found that the deviation caused is 30∘ The angle of prism is 60∘ What will be the angle between the ray inside the prism and the base of the prism .

Answer 1

hey mate here is your answer dear

We know that μ=sin(A+δm2)sinA2μ=sin⁡(A+δm2)sinA2

2–√=sin(60+δm2)sin302=sin⁡(60+δm2)sin⁡30

From this condition we observe that if δ=30∘δ=30∘ the expression hold c.

Also given that the deviation caused is 30∘30∘

∴∴ At minimum deviation condition the ray travels parallel to the base inside the prism.

The angle between the ray and base inside the prism is zero.

hope it helps you dear..