A ray of light is incident on a rectangular block of glass of index of refraction 1.450cm at an angle of 40 degree as shown in the figure. if the thickness of the block is 4.00 cm. find the amount d by which the ray is deviated.
Answers
Answered by
3
Answer:
There could be error as i used small angle approximation... But the method is given
Answer = 4 sin40
Explanation:
If u know value of sin40 then find x amd procced accordingly
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Answered by
7
Hey Dear,
◆ Answer -
Deviation = 1.289 cm
● Explanation -
# Given -
i = 40 °
n = 1.45
t = 4 cm
# Solution -
According to Snells law -
n = sini / sinr
sinr = sini / n
sinr = sin40° / 1.4
sinr = 0.6428 / 1.4
sinr = 0.459
r = 27.33°
Ray of light is expected to fall at -
d = t.tani
d = 4 × tan40°
d = 3.356 cm
Ray of light actually falls at -
d' = t.tanr
d' = 4 × tan27.33°
d' = 2.067 cm
Amount by which ray of light is deviated is -
∆d = d - d'
∆d = 3.356 - 2.067
∆d = 1.289 cm
Therefore, ray of light deviates by 1.289 cm.
Hope this helped you.
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