a ray of light is incident on a transparent surface from air at an angle of incident 45° and it deviates through 15° . find the refractive index of the transparent surface
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Answer:
sin45/sin15 = 1/√2/(sin45cos30-cos45sin30)
= 1/√2/(1/^2*√3/2 - 1/√2*1/2)
= 1/√2/(√3/2√2 - 1/2√2)
= 1/√2/(√3-1) /2√2
=2√2/√2(√3-1)
√2 cancells
= 2/(√3-1)
we can rationalise
= 2(√3+1) / 2
= √3+1
= 2.73
transperant surface is little more denser than diamond.
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