Question

A ray of light is incident on the surface of transparent medium at an angle of 45° and is refracted
in the medium at an angle of 30°. What will be the velocity of light in the transparent medium?
(1) 1.96 x 108 m/s
(2) 2.12 x 108 m/s
(3)
2.65 x 108 m/s
(4)
1.25 x 108 m/s.​

Answer 1

Dear Student,

● Answer -

(2) 2.12x10^8 m/s

● Explaination -

# Given -

i = 45°

r = 30°

# Solution -

Refractive index of transparent slab is given by -

n = sini / sinr

n = sin45° / sin30°

n = 0.7071 / 0.5

n = 1.414

Velocity of light in transparent medium is -

v = c / n

v = 3×10^8 / 1.414

v = 2.121×10^8 m/s

Therefore, velocity of light in transparent medium is 2.121×10^8 m/s.

Thanks dear. Hope this helps you...

Answer 2

Answer:

2.12×10^8m/s

Explanation:

hope you will get solution easily

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