Question

A ray of light is incident through glass, with refractive index 1.52 on an interface separating glass and water with refractive index 1.32. What is the angle of refraction if the angle of incidence of the Ray in glass is 25 degrees

Answer 1

The angle of refraction=$29.1^{\circ}$

Step-by-step explanation:

Refractive index of glass=$n_1=1.52$

Refractive index of water=$n_2=1.32$

Angle of incidence of the ray in glass=$\theta_1=25^{\circ}$

Snell's law:

$n_1sin\theta_1=n_2sin\theta_2$

Where$n_1=$ Incident index

$n_2$=Refracted index

$\theta_1$=Incident angle

$\theta_2$=Refracted angle

By using this law

$1.52 sin 25=1.32sin\theta_2$

$\frac{1.52\times 0.423}{1.32}=sin\theta_2$

$sin\theta_2=0.487$

$\theta_2=sin^{-1}(0.487)=29.1^{\circ}$

Hence, the angle of refraction=$29.1^{\circ}$

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