Question

.A ray of light is incident through glass, with refractive index 1.52, on an interface separating glass and water with refractive index 1.32. What is the angle of refraction if the angle of incidence of the ray in glass is 25 °?

Answer 1

Thus the value of angle of refraction is 29.1°

Explanation:

We are given data:

• Refractive index of glass = 1.52
• Refractive index of water = 1.32
• Angle of incidence "i" = 25°

To find: Angle of refraction "r" = ?

Solution:

Using Snell's law:

n1 ( Glass) = 1.52

n2 (Water) = 1.32

n1 sin (i) = n2 sin t

1.52 sin (25°) = 1.32 sin r

r =  [arc sin (1.52 / 1.32) sin 25° ]

r = 29.1°

Thus the value of angle of refraction is 29.1°