a ray of light is reflected from a plane mirror so that the angle between the incident and the reflected rays is 60°. If the mirror is rotated to increase the angle of incidence by 3°, what will be the new angle between the incident and reflected rays?
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the angle between incident and reflected will be 63degree
Bunti360:
The answer is 66° I think.
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The angle between incident ray and normal = the angle between normal and reflected ray !
let angle between incident ray and normal be I,
and angle between normal ray and reflected ray be R,
=> I = R
Now according to data angle between incident ray and normal ray is given as 60°,
We can write angle between incident ray and normal ray as I + R
Now I + R = 60°
But we know that I = R
Now 2I = 60°
I = R = 30°
now when the angle of incidence is increased by 3°,
The new angle of incidence = 30° + 3° = 33°,
The new angle of reflection will also be 33°,
So now the new angle between angle of reflected ray and incident ray is 33°+33°
= 66°,
So the answer is 66° !!
let angle between incident ray and normal be I,
and angle between normal ray and reflected ray be R,
=> I = R
Now according to data angle between incident ray and normal ray is given as 60°,
We can write angle between incident ray and normal ray as I + R
Now I + R = 60°
But we know that I = R
Now 2I = 60°
I = R = 30°
now when the angle of incidence is increased by 3°,
The new angle of incidence = 30° + 3° = 33°,
The new angle of reflection will also be 33°,
So now the new angle between angle of reflected ray and incident ray is 33°+33°
= 66°,
So the answer is 66° !!
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