Question

A ray of light is sent along the line which passes through the point 2,3 the ry is reflected from the point p on x axis if the reflecte ray passes throught he point 6,4 then coordinates of p are

Answer 1

to find P
find reflection of A on Xaxis, A' = (2,-3)
join A'B..... equation of line passing through A', B
$\frac{y-4}{x-6} = \frac{(-3-4)}{(2-6)}$

 P is the x intercept  on xaxis =(3.71,0)

Answer 2

Step-by-step explanation:

• So we have the x and y axis and a ray is incident on the x axis at a point m through a point (2,3) and is refracted by the point (6,4) and this point is P. Now we have the image of incident ray appearing on the y axis which will be (2,-3). Let this point be Q. So we have the coordinates of P and Q.

• So  the equation of line PQ will be
•                     So y – y1/ x – x1 = y2 – y1 / x2 – x1
•                       So y + 3 / x - 2 = 4 + 3 / 6 – 2
•                              Or y + 3 = 7 / 4 (x – 2)
• simplifying we get  4y + 12 = 7x – 14
•                                    7x – 4y = 26
• Now coordinate of y axis is zero, so putting y = 0 in the above equation we get
•                                     7x = 26
•                                    Or x = 26/7
• So the coordinates of m is (x,0) and so x = 26/7
• So we get coordinates as m(26/7,0)

Reference link will be

https://brainly.in/question/49482907