Question

A ray of light is traveling from the medium water to a medium of refractive index 1.5
If the iw = 4/3 then the critical angle for the second medium

​

Answer 1

Answer:

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Answer 2

Answer:

When a light ray travels from denser to rarer medium, then the angle of incidence for which the refracted ray becomes parallel to the interface(∠r=90

∘

), is known as critical angle for that pair of media.

Here, the denser medium is Glass μ

g

=

3

5

&

the rarer medium is water μ

w

=

3

4

Applying Snell's law at the interface of the two media, we have

μ

g

×Sin i

c

=μ

w

×Sin r

From definition, we know,

∠r=90

∘

⇒μ

g

×Sin i

c

=μ

w

×Sin 90

∘

⇒

3

5

×Sin i

c

=

3

4

⇒Sin i

c

=

(

3

5

)

(

3

4

)

⇒Sin i

c

=

5

4

⇒i

c

=Sin

−1

(

5

4

)

Explanation:

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