Question

a ray of light passes from glass ( ng=1.52) of water (nw=1.33). What is critical angle of incidence​

Answer 1

Answer:

θc=61°

Explanation:

n1sinθc=n2sin90

θc  =  sin¬1(n2/n1)

θc  =  sin¬1(1.33/1.52)

θc=61°

We can use Snell's law to determine the critical angle since we know that when the angle of incidence equals the critical angle, the angle of refraction is 90°.So by putting values to formula we can compute it. Remember that for total internal reflection the incident ray is always in the denser medium.