Question

A ray of light passes through the point (8, 3) and is reflected at (14, 0) then the equation of reflected ray is ax +by +c=0 where (a+b+c)a+b+cis​

Answer 1

Answer:So, to find reflected ray light, we have to find image of (8,3) on x-axis i.e. p(x  

1

​  

,y  

1

​  

)

y=0

0

x  

1

​  

−8

​  

=  

1

y  

1

​  

−3

​  

=−2  

1

(3)

​  

 

x  

1

​  

=8,y  

1

​  

=−3

p(8,−3)

∴ equation of line passing through p(8,−3) and (14,0)

⇒y=  

2

+1

​  

(x−14)

⇒2y=x−14

HOPE U UNDERSTAND

Step-by-step explanation: