Question

A ray of light passing through an equilateral prism in such a manner that the angle of incidence

Answer 1

I think question is

A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and each one is equal to 3/4th the angle of prism. Then angle of deviation is

i + e = A+ d

i --->angle of incidence

e--->emergence

A--->angle of prism

d---->angle of deviation

i=e= (3/4)A

(3/4)A+(3/4)A=A+d

1.5 A-A=d

d=A/2

A=60 degree (equilateral prism)

d=30 ..

Answer 2

Answer:

In an equilateral triangle all angles are 60°

angle i = angle e = 3/4A

i+e= A +d

3/4A +3/4A = A + d

1.5A = A + d

1/2A =d

d=1/2 .60°

d= 30°