A ray of light passing through an equilateral triangular glass prism from air undergoes minimum deviation when angle of incidence is 3/4th of the angle of prism. Calculate the speed of light in the prism. ?
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Here, the Angle of the prism, A=60
o
The angle of incidence, i=
4
3
×60
i+e=A+δ
e is emergence angle
where δ is the deviation angle
At minimum deviation δ=δ
min
i=e
2i=A+δ
min
2×45=60+δ
min
δ
min
=30
By prism law,
μ=
sin
2
A
sin
2
A+δ
min
μ=
sin
2
60
sin
2
60+30
=
2
2
=1.41
Let v be the velocity of light in a prism
v=
μ
c
=
1.41
3×10
8
=2×10
8
m/s
Hope This Helps.
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