Question

a ray of light passing through the prism having refractive index√2 suffers minimum deviation. It is found that angke of incidence is double the angle of refraction within the prism. Find the angle of prism​



answer correctly

Answer 1

Answer:

Explanation:

let  ∠i  denote incidence angle and  ∠r  denote refracted angle. Given:

∠i=2∗∠r  

Now by Snell’s Law applying at interface of Prism:

sinisinr=sin(2r)sinr=2sinr∗cosrsinr=2cosr=2–√  

Where we have used trignometric identity:

sin2x=2sinx∗cosx  

Therfore we have:

cosr=2√2=12√⇒r=45∘