Question

A ray of light strikes a glass slab 5 cm thick, making an angle of incidence equal to 30⁰.
(a) Make a ray diagram showing the emergent ray and refracted ray through the glass block.
(Note:– Refractive index of glass is 1.5)
(b) Measure the lateral displacement of the ray.
(Note:– sin 19.5⁰ = 1/3)
______________________

⚡No irrelevent answers​

Answer 1

Answer:

$\huge\mathfrak\purple{given:-}$

Refractive index(n) = 1.5°

Angle of incidence(i) = 30°

$\huge\mathfrak\purple{\: law \: used:-}$

Snell law

$\huge\mathfrak\purple{solutiom:-}$

$\mathtt \blue{By \: Snell \: law \: \frac{sin \: i}{sin \: r} = \: n }$

$\mathtt \blue{ \sin(r) = \frac{ \sin(i) }{n} }$

$\mathtt \blue{ = \frac{ \sin(30 \: degree) }{1.5} }$

$\mathtt \blue{ = \frac{ \frac{1}{2} }{1.5} }$

$\mathtt \blue{ = \frac{1}{3} }$

$\mathtt\blue{r = 19.5°(sin \: 19.5° = 1/3)}$

Now calculate lateral displacement

Formula used:-

$\mathtt\blue{lateral \: displacement = t× \frac{ \sin(i - r) }{ \cos \: r} }$

Now substitute the value

$\mathtt\blue{lateral \: displacement \: = 5 \times \frac{ \sin(30° - 19.5°) }{ \cos(19.5°) } }$

$\mathtt\blue{lateral \: displacement \: = 5 \times \frac{ \sin(10.5°)}{ \cos(19.5°) } }$

$\mathtt \blue{lateral \: displacement \: = \: 0.97cm}$

Nearly 1 cm

Explanation:

I hope this helps you buddy :)

Answer 2

Answer:

Formula used:

μ=sinisinr

Lateral Displacement=t×sin(i−r)cosr

Explanation:

hope it helps you ☺️✌️