Question

A ray of light takes 10power-9 second to cross a glass slab of refractive index 1.5. The thickness of the slab will be ​

Answer 1

We will assume here that the ray was incident and emerged normal to the glass slab surface.

As we know that, refractive index, u = c/v

v = c/u

v = (3x10^8)/1.5

v = 2x10^8 m/s

Now distance = speed x time

d = vt

d = (2x10^8)(10^-9)

d = 0.2 m

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Answer 2

Answer:

Explanation:

As we know that, refractive index, u = c/v

v = c/u

v = (3x10^8)/1.5

v = 2x10^8 m/s

Now distance = speed x time

d = vt

d = (2x10^8)(10^-9)

d = 0.2 m