Question

A ray of light travelling from air enters a liquid at an angle of 45° with the normal. If the
corresponding angle of refraction is 30°, find out the refractive index of the liquid with respect
to air.​

Answer 1

Answer:

hope this answer will help you

Answer 2

Given : i=450   r=300  (μair)

To find : μwater

Solution: From snell's law

μ1sini=μ2sinr

μairsin450=μwsin300

21=2μw

μw2

Now let us take that for angle of incidence α the angle between reflected ray and refracted ray be 900 then

α+r+900=1800/900   (since i = angle of reflection from laws of reflection)

Hence r=90−