Question

A ray of light travelling from air to water .what is angle of incidence when refractive angle is 45. The refractive index of. water is 1.32

Answer 1

we know that

∠i ÷∠r = index

∠i ÷45 = 1.32

∠i = 1.32×45

∠i = 59.4

I HOPE ITS HELPFUL

Answer 2

Answer:

Step-by-step explanation:

Refractive index = sin i / sin r

Therefore,

sin i = refractive index × sin r

Putting the values,

sin i = 1.32 × sin 45

sin i = 0.94(approx.)

<i = sin inverse(0.94)