Question

A ray of light travelling in a vacuum (refractive index = 1) is incident upon a glass plate (refractive index = 1.3). It hits with an angle of incidence of 45 degrees. If the angle of incidence increases to 50 degrees what is the new angle of refraction?​

Answer 1

Explanation:

Snell's law states that ratio of sine of angle of incidence to sine of angle of refraction is a constant. This constant is called the refractive index of the medium. Hence:

n

ga

=

sinr

sinr

=

sin24

∘

sin37

∘

=

0.40

0.60

=1.5

Answer 2

Answer:

The new angle of refraction is (sin)⁻¹0.589.

Explanation:

From the snells law, we have,

$\mu_1sini=\mu_2sinr$     (1)

Where,

μ₁=refractive index of the medium in which light is present

i=angle incidence

μ₂=refractive index of the medium in which light is about to travel

r=angle of refraction

From the question we have,

μ₁=1

μ₂=1.3

i₁=45°

i₂=50°

Since we have to find the angle of refraction at i=50°.So, equation (1) can be written as,

$\mu_1sin50\textdegree=\mu_2sinr$       (2)

By substituting the required values in equation (2) we get;

$1\times sin50\textdegree=1.3\times sinr$

$sinr=\frac{0.766}{1.3}$

$sinr=0.589$

$r=(sin)^-^10.589$

Hence, the new angle of refraction is (sin)⁻¹0.589.