Question

-A ray of light travelling in air falls on the surface of a transparent slab. the ray makes an angle an angle of 45degree with the normal to the surface .find the angle made by the refracted ray with the normal within the slab in degree. refractive index of the material of the slab is Root 2​

Answer 1

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Answer 2

Given info : A ray of light travelling in air falls on the surface of a transparent slab. the ray makes an angle an angle of 45° with the normal to the surface. refractive index of the material of the slab is √2.

To find : The angle made by the refracted ray with the normal within the slab in degree.

solution : using Snell's law, μ₁sini = μ₂sinr

here first medium is air,

so, μ₁ = 1 and incident angle , i = 45°

now after refraction, the ray makes an angle r with the normal.

refractive index of slab, μ₂ = √2

so, 1 × sin45° = √2 × sinr

⇒1 × 1/√2 = √2 × sinr

⇒1/2 = sinr

⇒r = 30°

Therefore the angle made by the refracted ray with the normal within the slab is 30°.

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