Question

a ray of light travelling in air in incident on the plane surface of a transparent medium the angle of incidence is 45 degree and that of refraction is 30 degree the refractive index of a medium is​

Answer 1

Answer:

Refractive index=sin45/sin30

=sin45=1/√2

=sin30=1/2

Refractive index=1/√2/1/2

=1×2/√2

=2/√2

=√2 is the answer

Answer 2

Answer:

In the given question we are asked to calculate the refractive Index of a medium. Let us proceed to the question.

Explanation:

Prior to calculating the refractive index of a medium, let us first understand what is refractive index.

What is Refractive Index?

Refractive Index of a Medium is basically a number that denotes the capability of that optical medium to bend the light rays entering it. In general, it is usually calculated as speed of light in vacuum divided by speed of light in that optical medium. It is usually denoted by either n or μ.

According to Snell's Law, ratio of sine of incidence of a light ray to the sine of refraction always remains constant and is equal to refractive index of that medium. Therefore,

sin i / sin r = μ                                    (where μ = refractive index)

Now, proceeding to question.

Given: angle of incidence(i) = 45°

           angle of refraction(r) = 30°

To find: Refractive Index(μ)

Hence, from the formula mentioned above, we can easily calculate μ.

μ = sin 45° / sin 30°

  = (1/√2)÷(1/2)

  = 2/√2

μ  = √2

Hence, Refractive Index(μ) of the optical medium is √2.