Question

A ray of light travelling in air is incident on a face of a rectangular slab and comes out from the opposite face. the angle between the incident ray and the normal to the surface is 30 degree. what is the angle between the ray coming out of the slab and the normal to the face from which it comes out?

Explain it !!

❌Copied Answer will directly Reported on the Spot.❌​

Answer 1

Solution :

incidence angle = 30°

emergence angle => angle between ray coming out and normal face from which it's come

according to fig

=> r = e .......(1)

we need to calculation the angle between ray coming out and normal to face from which if comes out

put in equation 1

=> e = 30°

=> Hence the angle between between ray coming out of slab and the normal is 30°

Answer 2

$\huge\sf\pink{Answer}$

☞ Your answer is 30°

━━━━━━━━━━━━━

$\huge\sf\blue{Given}$

✭ A ray of light is incident on a rectangular slab and comes out from the opposite side

✭ The angle between the incident ray & the normal is 30°

━━━━━━━━━━━━━

$\huge\sf\gray{To \:Find}$

◈ The angle between the ray coming out and the normal?

━━━━━━━━━━━━━

$\huge\sf\purple{Steps}$

$\sf \large\underline{\underline{\sf Concept}}$

»» Angle of Emergence is this angle between the normal and the ray that comes out of the slab

»» Incident Ray is always parallel to the ray that emerges out

»» E = I

━━━━━━━━━━

So as we are given the angle of incidence is 30° then,

$\underline{\boxed{\sf Angle \ of \ Incidence = Angle \ of \ Emergence}}$

Substituting the given values,

➝ $\sf Incident \ Angle = Angle \ of \ Emergence$

➝ $\sf \orange{30^{\circ} = Angle \ of \ Emergence}$

$\sf \large\star\: Diagram \: \star$

$\setlength{\unitlength}{1 cm}\begin{picture}(20,10)\linethickness{1.25}\put(1,1){\line(0,1){3}}\put(1,4){\line(1,0){4}}\put(5,1){\line(0,1){3}}\put(1,1){\line(1,0){4}}\put(4,4){\line(4,3){1.3}}\put(4.5,4.1){\sf 30}\put(2,0.6){\sf 30}\put(3,1){\line(1,3){1}}\put(1.7,0){\line(4,3){1.3}}\end{picture}$

━━━━━━━━━━━━━━━━━━