Question

A ray of light travels from water to air is shown below given that the refractive index of air is 1 and refractive index of water is 1.3 what is the angle of incidence

Answer 1

The angle of incidence is 1.3

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Answer 2

Given:

Refractive Index of air = 1

Refractive index of water = 1.3

Light travels from water to air.

To Find:

The angle of incidence.

Solution:

According to Snell's Law

μ$_{1}$ sin i = μ$_{2}$ sin r

Also, when light travels from a denser medium to a rarer medium, it can undergo Total Internal Reflection.

When the angle of refraction = 90°, and light passes from the interface

Then the angle of incidence is called the Critical Angle.

So, sin i = μ$_{2}$  sin r/ μ$_{1}$

Putting values in the equation

⇒ sin c = $\frac{1}{1.3}$ × sin 90°

⇒ sin c = 1/ 1.3   ( ∵ sin 90° = 1)

⇒ sin c = 0.769 = sin i

⇒ i = $sin^{-1}$ 0.769

Hence, the angle of incidence is $sin^{-1}$ 0.769.