A reaction is 20 % complete in 20 min . Calculate the time required for 80 % completion of reaction
, If reaction follows the first order .
Answers
Answered by
0
Answer:
PSP
Explanation:
For first order reaction we have:-
K=
t
1
ln(
a−x
a
) −(i)
where, K= rate constant
t= time
a= initial concentration of the reactant
x= amount of reactant reacted in time t
Case I: t=20 min
x=
100
20
×a⇒x=0.2a (∵20 % reaction is complete)
⇒ a−x=0.8a
Answered by
0
Answer:
20 % require 20 min means 1 % require 1 min , then 80% require 80 min
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