Chemistry, asked by indrajadhavrao7385, 1 year ago

A reaction is first order in reactant A and second order in reactant B. How is the rate of this reaction affected when (i) concentration of B is increased to three times (ii) concentration of both A and B is doubled?

Answers

Answered by tashubhatt01042
20

It is given that a reaction is first order in reactant A and second order in reactant B

rate = k[a][b] square

where r is the rate of reaction and k is the rate constant of the reaction

now on equating we will get the value equals 9

similarly in second we will get the value as 8

If it is helpful plz mark as brainliest

Similar questions