A reaction is first order in reactant A and second order in reactant B. How is the rate of this reaction affected when (i) concentration of B is increased to three times (ii) concentration of both A and B is doubled?
Answers
Answered by
20
It is given that a reaction is first order in reactant A and second order in reactant B
rate = k[a][b] square
where r is the rate of reaction and k is the rate constant of the reaction
now on equating we will get the value equals 9
similarly in second we will get the value as 8
If it is helpful plz mark as brainliest
Similar questions