Chemistry, asked by Nikkisely, 11 months ago

a reaction is second order with respect to a reactant .How the rate of the reaction be affected if concentration of the reactant is reduced to half?

Answers

Answered by Puneetgenius
2

Answer:

A reaction is second order with respect to a reactant.

Rate =k[A]

2

(i) If the concentration of the reactant is doubled, the rate of reaction becomes 4 times .

(ii) If the concentration of the reactant is reduced to half, the rate of reaction becomes one fourth.

Answered by saharounak093
0

Answer: One-fourth

Explanation:Usually for a second order reaction

Rate=k[A^2]

If the concentration [A] changes to [1/2A] then

Rate=k[1/2A]^2

Rate=1/4k A^2

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