Question

A reaction mixture for the production of NH3 gas contains 250g of N2 gas and 50g of H2 gas under suitable conditions. ldentify the limiting reactant, if any and calculate the mass of NH3 gas produced.​

Answer 1

Answer:

Answer:mass of NH3 = 282.2 gH2 is the limiting reactantExplanation:

Answer 2

The balanced chemical equation for the reaction is :-

N₂ + 3H₂ → 2NH₃

Number of moles of N₂ :-

= Given Mass/Molar mass

= 250/28

= 8.93 moles

Number of moles of H₂ :-

= Given Mass/Molar mass

= 50/2

= 25 moles

From the balanced equation :-

8.93 mole of N₂ will react with :-

=> 3×8.93 = 26.79 mole of H₂.

Here, we are given more moles of N₂ than H₂, therefore N₂ is in excess and some of it will remain unreacted when the reaction is over.

Thus, H₂ is the limiting reagent/reactant and will control the amount of product.

Now :-

∵ 6g H₂ → 34g NH₃

∴ 50g H₂ → 50×34/6 = 283.33g NH₃

Thus, mass of NH₃ gas produced is 283.33g.