Question

A reaction system in equilibrium according to the equation 2 SO2+ O2 <=> 2SO3in 1 litre reactionvessel at a given temperature was found to contain 0.11 mol of SO2, 0.12 mol of SO3and 0.05 mol ofO2. Another 1 litre reaction vessel contains 64 g of SO2at the same temperature. What mass of O2mustbe added to this vessel in order that at equilibrium half of SO2is oxidised to SO3?​

Answer 1

Answer:1.344

Explanation:k=0.12^2/(0.05*0.11^2)

64/64=1 mole SO2

mole O2=0.5^2/(0.5^2*x) ⇒x=0.042 mole O2

0.042*32=1.344 g O2