Chemistry, asked by adityawesome5959, 9 months ago

A reaction was found to be second order with respect to the
concentration of carbon monoxide. If the concentration of
carbon monoxide is doubled, with everything else kept the
same, the rate of reaction will
(a) remain unchanged (b) triple
(c) increase by a factor of 4 (d) double

Answers

Answered by Fatimakincsem
0

The rate of reaction will be r = 4 K [A]^2 . Which is four times it's initial rate.

Correct answer is option (D).

Explanation:

  • The reaction is second order kinetics. the only reactant is CO2.
  • Let us assume it as 'A'.
  • We know that for second order reaction.
  • r=k[A] ^2

Any change in the concentration of CO2 will have it's effect on the rate of the reaction.

The rate of the reaction will be increased when the concentration of carbon monoxide is doubled by four times.

Therefore r = k [2A]^2}

r = 4 K [A]^2

Thus the rate of reaction will be r = 4 K [A]^2 . Which is four times it's initial rate.

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