Question

A reactive metal which burns with golden flame forma a
compound with bicarbonate

Answer 1

Answer:

Element A is sodium metal(Na) as it burns with a golden flame.

Element B with atomic number 17 is chlorine (Cl).

Sodium and chlorine combine to form sodium chloride, NaCl(compound C).

The reaction can be written as:

2Na+Cl

2

→2NaCl

Aqueous solution of NaCl on electrolysis gives the compound D, sodium hydroxide(NaOH). The equation for this can be written as:

2NaCl(aq)+2H

2

O(l)→2NaOH(aq)+Cl

2

(g)+H

2

(g)