A reagent bottle of h2o2 labeled as 10v. The oxygen gas liberated from 2ml of this h2o2 is _______ ml
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4
Answer:
1
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Answered by
0
Answer:
1 volume of H
2
O
2
will give off 10 volumes of O
2
at STP.
The equation is: 2H
2
O
2
→2H
2
O+O
2
.
10 litres correspond to 0.409 moles of O
2
.
Therefore, the moles of H
2
O
2
are 0.818 = 27.812 g of H
2
O
2
.
The density of H
2
O
2
is 1.463 g/mL, so 27.78 grams is about 19.0 mL or 0.019 L.
Therefore, the percentage by volume is
1
0.019×100
=1.9 % by volume.
So, the nearest integer is 2%.
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